As a specific example of the application of perturbation theory,
we consider the Van der Waals equation of state. Let
be given by a pair potential:
with
This potential is known as the hard sphere potential.
In the low-density limit, the radial distribution function can be
shown to be given correctly by
or
is taken to be some arbitrary attractive potential,
whose specific form is not particularly important. Then, the
full potential
might look like:
Now, the first term in
is
where
is a number that depends on
and the specific form of
.
Since the potential
is a hard sphere potential,
can be determined analytically. If
were 0, then
would describe an ideal gas and
However, because two particles may not approach each other closer than
a distance
between their centers, there is some excluded volume:
If we consider two hard spheres at closest contact and draw the smallest
imaginary sphere that contains both particles, then we find this
latter sphere has a radius
:
Hence the excluded volume for these two particles is
and hence the excluded volume per particle is just half of this:
Therefore Nb is the total excluded volume, and we find that, in the low density limit, the partition function is given approximately by
Thus, the free energy is
If we now use this free energy to compute the pressure from
we find that
This is the well know Van der Waals equation of state. In the very low
density limit, we may assume that
, hence
Thus,
from which we can approximate the second virial coefficient:
A plot of the isotherms of the Van der Waals equation of state is shown below:
The red and blue isotherms appear similar to those of an ideal gas, i.e., there is a monotonic decrease of pressure with increasing volume. The black isotherm exhibits an unusual feature not present in any of the ideal-gas isotherms - a small region where the curve is essentially horizontal (flat) with no curvature. At this point, there is no change in pressure as the volume changes. Below this isotherm, the Van der Waals starts to exhibit unphysical behavior. The green isotherm has a region where the pressure decreases with decreasing volume, behavior that is not expected on physical grounds. What is observed experimentally, in fact, is that at a certain pressure, there is a dramatic, discontinuous change in the volume. This dramatic jump in volume signifies that a phase transition has occurred, in this case, a change from a gaseous to a liquid state. The dotted line shows this jump in the volume. Thus, the small flat neighborhood along the black isotherm becomes larger on isotherms below this one. The black isotherm just represents a boundary between those isotherms along which no such phase transition occurs and those that exhibit phase transitions in the form of discontinuous changes in the volume. For this reason, the black isotherm is called the critical isotherm, and the point at which the isotherm is flat and has zero curvature is called a critical point.
A critical point is a point at which
Using these two conditions, we can solve for the critical volume
and critical temperature
:
and the critical pressure is therefore
Using these values for the critical pressure, temperature and volume, we can show that the isothermal compressibility, given by
diverges as the critical point is approached. To see this, note that
Thus,
It is observed that at a critical point,
diverges, generally, as
.
To determine the heat capacity, note that
so that
Then, since
it follows that
The heat capacity is observed to diverge as
.
Exponents such as
and
are known as
critial exponents.
Finally, one other exponent we can easily determine is related to
how the pressure depends on density near the critical point.
The exponent is called
, and it is observed that
What does our theory predict for
? To determine
we expand the equation of state about the critical density
and temperature:
The second and third terms vanish by the conditions of the critical point. The third derivative term can be worked out straightforwardly and does not vanish. Rather
Thus, we see that, by the above expansion,
.
The behavior of these quantities near the critical temperature determine three critical exponents. To summarize the results, the Van der Waals theory predicts that
The determination of critical exponents such as these is
an active area in statistical mechanical research. The reason
for this is that such exponents can be grouped into
universality classes - groups of systems with exactly the
same sets of critical exponents. The existence of universality
classes means that very different kinds of systems exhibit essentially
the same behavior at a critical point, a fact that makes the
characterization of phase transitions via critical exponents
quite general. The values obtained above for
,
and
are known as the mean-field exponents and shows that
the Van der Waals theory is really a mean field theory.
These exponents do not agree terribly well with experimental
values (
,
). However, the simplicty
of mean-field theory and its ability to give, at least, qualitative
results, makes it, nevertheless, useful. To illustrate universality
classes, it can be shown that, within mean field theory, the
Van der Waals gas/liquid and a magnetic system composed of
spins at particular lattice sites, which composes the
so called Ising model, have exactly the same mean field
theory exponents, despite the completely different nature
of these two systems.
Another problem with the Van der Waals theory that is readily
apparent is the fact that it predicts
for certain values of the density
. Such behavior is
unstable. Possible ways of improving the approximations used
are the following: